• From: Egypt- Saudi Arabia
  • Registered: 2009-12-12
  • Posts: 968

Topic: Math.Min ,max question

if Today’s low is lower than the previous 15 lows then buy

what is the mistake 

public override void Calculate(SlotTypes slotType)
        {
            // Reading the parameters
            int iFirstBar = 16;

            double[] adUp = new double[Bars];
        double[] adDn = new double[Bars];

            for (int iBar = 16; iBar < Bars - 1; iBar++)
            {
                // Long trade
                                //1. Today’s low is lower than the previous 15 lows.
                if (Low[iBar - 15] < Math.Min(Low[iBar - 1], Low[iBar - 15]))
                adUp[iBar] = 1;

Thanks in advance

  • footon
  • footon
  • ◄≡≡≡►
  • Offline
  • Registered: 2009-08-17
  • Posts: 2,969

Re: Math.Min ,max question

You have to loop through all 15 bars to find the low.

I'd do something like this, based on Donchian Channel indi:

for (int iBar = iFirstBar; iBar < Bars; iBar++)
            {
                
                double dMin = double.MaxValue;
                for (int i = 1; i < 16; i++)
                {
                    
                    if (Low[iBar - i]  < dMin) dMin = Low[iBar - i];
                
                }
                
                 if (Low[iBar-1] < dMin)
                    long[iBar]=1;
             }
  • From: Egypt- Saudi Arabia
  • Registered: 2009-12-12
  • Posts: 968

Re: Math.Min ,max question

thanks footon

So i can write the code for buy setup as follow 

public override void Calculate(SlotTypes slotType)
        {
            // Reading the parameters
            int iFirstBar = 16;

            double[] adUp = new double[Bars];
            double[] adDn = new double[Bars];

            for (int iBar = 16; iBar < Bars - 1; iBar++)
            {
                // Long trade
                //1. Today’s low is lower than the previous 15 lows.
                double dMin = double.MaxValue;
                for (int i = 1; i < 16; i++)
                {
                    if (Low[iBar - i] < dMin) dMin = Low[iBar - i];
                }

                if (Low[iBar - 1] < dMin)
                    adUp[iBar] = 1;

 

Is that right !!!!!

  • footon
  • footon
  • ◄≡≡≡►
  • Offline
  • Registered: 2009-08-17
  • Posts: 2,969

Re: Math.Min ,max question

Seems to be right. Although I would use the main for loop like in my previous post:

for (int iBar = iFirstBar; iBar < Bars; iBar++)