Forex Software — Math.Min ,max question

Re: Math.Min ,max question

2013-03-13T21:02:16Z

Seems to be right. Although I would use the main for loop like in my previous post:

for (int iBar = iFirstBar; iBar < Bars; iBar++)

Re: Math.Min ,max question

2013-03-13T20:53:31Z

thanks fotoon

So i can write the code for buy setup as follow

public override void Calculate(SlotTypes slotType)
        {
            // Reading the parameters
            int iFirstBar = 16;

            double[] adUp = new double[Bars];
            double[] adDn = new double[Bars];

            for (int iBar = 16; iBar < Bars - 1; iBar++)
            {
                // Long trade
                //1. Today’s low is lower than the previous 15 lows.
                double dMin = double.MaxValue;
                for (int i = 1; i < 16; i++)
                {
                    if (Low[iBar - i] < dMin) dMin = Low[iBar - i];
                }

                if (Low[iBar - 1] < dMin)
                    adUp[iBar] = 1;

Is that right !!!!!

Re: Math.Min ,max question

2013-03-13T20:28:06Z

You have to loop through all 15 bars to find the low.

I'd do something like this, based on Donchian Channel indi:

for (int iBar = iFirstBar; iBar < Bars; iBar++)
            {
                
                double dMin = double.MaxValue;
                for (int i = 1; i < 16; i++)
                {
                    
                    if (Low[iBar - i]  < dMin) dMin = Low[iBar - i];
                
                }
                
                 if (Low[iBar-1] < dMin)
                    long[iBar]=1;
             }

Math.Min ,max question

2013-03-13T19:56:35Z

if Today’s low is lower than the previous 15 lows then buy

what is the mistake

public override void Calculate(SlotTypes slotType)
        {
            // Reading the parameters
            int iFirstBar = 16;

            double[] adUp = new double[Bars];
        double[] adDn = new double[Bars];

            for (int iBar = 16; iBar < Bars - 1; iBar++)
            {
                // Long trade
                                //1. Today’s low is lower than the previous 15 lows.
                if (Low[iBar - 15] < Math.Min(Low[iBar - 1], Low[iBar - 15]))
                adUp[iBar] = 1;

Thanks in advance